Try This Month’s Challenge!

Are you a professional problem solver? If so, we invite you to submit your ‘Ponder This’ solution for this month’s challenge.

Ponder This Challenge:

Let b = (2^3^4^5) / (e^n), otherwise stated as “two to the power of (three to the power of (4 to the power of 5)) over e to the nth power”, where n is an integer such that

1 < b < e.
Find b, with an accuracy of 10 decimal digits.

IBM Research will post the names of those who submit a correct, original solution to their website! If you don’t want your name posted then please include such a statement in your submission. Send your submission to the webmaster.

If you have any problems you think we might enjoy, please send them in. All replies should be sent to:

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