Are you a professional problem solver? If so, we invite you to submit your ‘Ponder This’ solution for this month’s challenge.
Ponder This Challenge:
Let b = (2^3^4^5) / (e^n), otherwise stated as “two to the power of (three to the power of (4 to the power of 5)) over e to the nth power”, where n is an integer such that
1 < b < e.
Find b, with an accuracy of 10 decimal digits.
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